آخر الأخبار

جاري التحميل ...

Torque Ratios

       The performance of the motor is sometimes expressed in terms of comparison of various torques such as full load torque, starting torque and maximum torque. The comparison is obtained by finding out ratios of these torques.
1.1 Full load and Maximum Torque Ratio
In general,        Tα (s E22 R2)/(R22 +(s X2)2)  
Let                     s= Full load slip
...                       TF.L. α (s E22 R2)/(R22 +(s X2)2)  
and                    sm = Slip for maximum torque T
...                       Tα (s E22 R2)/(R22 +(s X2)2)

       Dividing both numerator and denominator by X22 we get,
But                       R2/X2 = s
                            TF.L./T = (s x 2 sm2)/(sm x (sm2+ sf2))
                             TF.L./Tm   = (2 s sm)/(sm2 + sf2)
1.1 Starting Torque and Maximum Torque Ratio
       Against starting with torque equation as,
                           T α  (s E22 R2)/(R22 +(s X2)2)  
Now for Tst,        s =1
                           Tst  α   (E22 R2)/(R22 +( X2)2)
While for Tm,       s = sm
 
       Dividing both numerator and denominator by X22 we get,
      Substituting             R2/X2 = sm
 
       Infact using the same method, ratio of any two torques at two different slip values can be obtained.
       Sometimes using the relation, R2 = a X2 the torque ratios are expressed interms of constant a as,
                            TF.L./T = (a sf )/(a2+ sf2)
and                       Tst/T= 2 a/ (1 + a2)
where                    a = R2/X2 = sm
Example 1 : A 24 pole, 50 Hz, star connected induction motor has rotor resistance of 0.016 Ω per phase and rotor reactance of 0.265 Ω per phase at standstill. It is achieving its full load torque at a speed of 247 r.p.m. Calculate the ratio of 
i) Full load torque to maximum torque   ii) starting torque to maximum torque
Solution : Given values are,
   P = 24,   f = 50 Hz,       R2 = 0.016 Ω,   X2 = 0.265 Ω,     N = 247 r.p.m.
               N= 120f / P = (120x50)/24 = 250 r.p.m.
                s= (N- N)/N = (250-247)/250 = 0.012 = Full load slip
                 sm = R2/X2 = 0.016/0.265 = 0.06037
i)              TF.L./T= (2 sm sf )/(sm2+ sf2) = (2 x 0.06037 x 0.012)/(0.060372 + 0.0122)
ii)              Tst/T = (2 sm )/(1 + sm2) = (2 x 0.06037)/(1 + 0.060372) = 0.1203

Sponsored links :

about author

hamada i'm hamada rageh electrical power engineer my talent to write articles about electrical engineering and i depend on google books site to write my articles

التعليقات


اتصل بنا

إذا أعجبك محتوى مدونتنا نتمنى البقاء على تواصل دائم ، فقط قم بإدخال بريدك الإلكتروني للإشتراك في بريد المدونة السريع ليصلك جديد المدونة أولاً بأول ، كما يمكنك إرسال رساله بالضغط على الزر المجاور ...

جميع الحقوق محفوظة

your electrical home